dannyelo•5mo ago

v.string().isOptional property not working

Hello, I saw available the isOptional property in the v.string() But I have an error after I use it in the property name.

Type 'string' is not assignable to type 'Validator<any, OptionalProperty, any>'.ts(2322)
(property) color: "required"

Type 'string' is not assignable to type 'Validator<any, OptionalProperty, any>'.ts(2322)
(property) color: "required"

Any suggestion?

3 Replies

lee•5mo ago

can you describe what you're trying to do, or give the full code? It's possible you want v.optional(v.string())

dannyeloOP•5mo ago

Yes, v.optional(v.string()) works ok. I just was curios I saw that property there. Thanks

lee•5mo ago

isOptional allows you to introspect a validator, so if you're given a validator you can determine whether it was constructed with v.optional. It's not useful for constructing new validators

v.string().isOptional property not working

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