1 reply

Does await block next query?

Is the sequential awaitawait blocking? Or does convex special magic sauce call them at the same time? As I'm typing out this question, I'm realizing it must block it in case the second query needs data from the first. But I guess I'll ask in case anyone else questions this.

const users1 = await promise.all(
  userIds.map((userId) => ctx.db.get(userId))
);

const users2 = await promise.all(
  userIds.map((userId) => ctx.db.get(userId))
);

const users1 = await promise.all(
  userIds.map((userId) => ctx.db.get(userId))
);

const users2 = await promise.all(
  userIds.map((userId) => ctx.db.get(userId))
);

const [users1, users2] = await Promise.all([
  await promise.all(
    userIds.map((userId) => ctx.db.get(userId))
  ),

  await promise.all(
    userIds.map((userId) => ctx.db.get(userId))
  )
]);

const [users1, users2] = await Promise.all([
  await promise.all(
    userIds.map((userId) => ctx.db.get(userId))
  ),

  await promise.all(
    userIds.map((userId) => ctx.db.get(userId))
  )
]);

Convex Community•7mo ago•

1 reply

Igor

Does await block next query?

const users1 = await promise.all(
  userIds.map((userId) => ctx.db.get(userId))
);

const users2 = await promise.all(
  userIds.map((userId) => ctx.db.get(userId))
);

const users1 = await promise.all(
  userIds.map((userId) => ctx.db.get(userId))
);

const users2 = await promise.all(
  userIds.map((userId) => ctx.db.get(userId))
);

const [users1, users2] = await Promise.all([
  await promise.all(
    userIds.map((userId) => ctx.db.get(userId))
  ),

  await promise.all(
    userIds.map((userId) => ctx.db.get(userId))
  )
]);

const [users1, users2] = await Promise.all([
  await promise.all(
    userIds.map((userId) => ctx.db.get(userId))
  ),

  await promise.all(
    userIds.map((userId) => ctx.db.get(userId))
  )
]);

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Does await block next query?

Does await block next query?

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