Sara•2w ago

can I do this type defenition like in typescript with v validator?

I tried doing:

const textData = literals('x','y','z');
const typeOfTextDataInRecord = v.record(textData, v.array(v.string()))

const textData = literals('x','y','z');
const typeOfTextDataInRecord = v.record(textData, v.array(v.string()))

same as in typescript in my brain as doing this:

 type textData = ['x','y','z'];
 type howWeDoTextData = textData[number]
 type typeOfTextDataInRecord = Record <howWeDoTextData,string[]>

 type textData = ['x','y','z'];
 type howWeDoTextData = textData[number]
 type typeOfTextDataInRecord = Record <howWeDoTextData,string[]>

3 Replies

Convex Bot•2w ago

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SaraOP•2w ago

update: I created an object that has keys and values and the type seems to resemble what I want.

const newType = v.object({key:textData, value:v.array(v.string())})

const newType = v.object({key:textData, value:v.array(v.string())})

sshader•2w ago

Yeah the best way of getting the validation you want is storing an array of objects with key and value types (and then unpacking them into a record or map in your code if you prefer). Fun fact -- TypeScript's Record type has some kind of funky behavior when the key is a union of literals example This is one of the reasons why we don't allow things like v.record(textData, <other validator>) and just allow things like v.record(v.string(), <other validator>)

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can I do this type defenition like in typescript with v validator?

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