Papa Johns•4mo ago

```

Validator<Record<string, any>, "required", any>): TableDefinition<Validator<Record<string, any>, "required", any>, {}, {}, {}>', gave the following error.
    Object literal may only specify known properties, and 'firstName' does not exist in type 'Validator<Record<string, any>, "required", any>'.

Validator<Record<string, any>, "required", any>): TableDefinition<Validator<Record<string, any>, "required", any>, {}, {}, {}>', gave the following error.
    Object literal may only specify known properties, and 'firstName' does not exist in type 'Validator<Record<string, any>, "required", any>'.

I am trying to use the firstName and lastname in my schema. But it is not allowing me to do so.

7 Replies

Hmza•4mo ago

Looks like your schema syntax might be a bit off. as I don't know more about your schema. can you confirm it follows this pattern

import { defineSchema, defineTable } from "convex/server";
import { v } from "convex/values";

export default defineSchema({
  users: defineTable({
    firstName: v.string(),
    lastName: v.string(),
//more fields
  }),
//more tables
});

import { defineSchema, defineTable } from "convex/server";
import { v } from "convex/values";

export default defineSchema({
  users: defineTable({
    firstName: v.string(),
    lastName: v.string(),
//more fields
  }),
//more tables
});

Papa JohnsOP•4mo ago

yes similar to that with some more utility related fields If I mention the tokenIdentifier field, it doesn't throw this error. I am trying to integerate Clerk and convex

Hmza•4mo ago

I see so its auth related! Are you defining custom table for auth users? You should check this repo out and see how convex schema and functions are defined https://www.convex.dev/templates/nextjs-app-router

Next.js 14 App Router

This example app showcases Convex backend powering a Next.js app.

Hmza•4mo ago

I think you’ll need that for JWT

Papa JohnsOP•4mo ago

Actually I am redefining the users table for my clerk authentication with some extra fields based on the clerk configuration. what is the syntax for optional Fields I was using v.string().isOptional and that was issue here.

jamwt•4mo ago

v.optional(v.string())

Papa JohnsOP•4mo ago

thanks for the reply.

```

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