CabalDAO
CabalDAO•3mo ago

Mapping defined types to other defined types

I have two types: 
export const ReferralOverviewStatus = v.union(
  v.literal("new"),
  v.literal("in_review"),
  v.literal("needs_review"),
  v.literal("accepted_awaiting_placement"),
  v.literal("accepted_won"),
  v.literal("accepted_lost"),
  v.literal("bed_hold"),
  v.literal("rejected")
);
export const ReferralOverviewStatus = v.union(
  v.literal("new"),
  v.literal("in_review"),
  v.literal("needs_review"),
  v.literal("accepted_awaiting_placement"),
  v.literal("accepted_won"),
  v.literal("accepted_lost"),
  v.literal("bed_hold"),
  v.literal("rejected")
);
And 
export const DecisionStatus = v.union(
  v.literal("accepted"),
  v.literal("rejected"),
  v.literal("needs_review")
);
export const DecisionStatus = v.union(
  v.literal("accepted"),
  v.literal("rejected"),
  v.literal("needs_review")
);
As you can see, DecisionStatus overlaps with ReferralOverviewStatus. In one mutation, I accept an args type of DecisionStatus and I want to pass it to a mutation that accepts an arg type of ReferralOverviewStatus. I've tried a bunch of different things but I still get typescript errors for all of these. How can I make this work?
6 Replies
Convex Bot
Convex Bot•3mo ago
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CabalDAO
CabalDAOOP•3mo ago
I made a manual type of just plain strings for ReferralOverviewStatus as : 
export type ReferralOverviewStatusType =
  | "new"
  | "in_review"
  | "needs_review"
  | "accepted_awaiting_placement"
  | "accepted_won"
  | "accepted_lost"
  | "bed_hold"
  | "rejected";
export type ReferralOverviewStatusType =
  | "new"
  | "in_review"
  | "needs_review"
  | "accepted_awaiting_placement"
  | "accepted_won"
  | "accepted_lost"
  | "bed_hold"
  | "rejected";
Then passed it like so: 
await ctx.scheduler.runAfter(0, internal.referralOverview.updateStatus, {
  referralId: args.referralId,
  status: args.decision as ReferralOverviewStatusType,
});
await ctx.scheduler.runAfter(0, internal.referralOverview.updateStatus, {
  referralId: args.referralId,
  status: args.decision as ReferralOverviewStatusType,
});
This seems to work. But is there any easier way than having to write separate plain js types that are really the same thing as the v type?
M Zeeshan
M Zeeshan•3mo ago
@CabalDAO have you tried this approach? 
status: args.decision as Doc<YOU_SCHEMA_TABLE_NAME>['filed name']
status: args.decision as Doc<YOU_SCHEMA_TABLE_NAME>['filed name']
e.g. 
import { Doc } from './_generated/dataModel';
type SkillType = Doc<"skills">['type'];
import { Doc } from './_generated/dataModel';
type SkillType = Doc<"skills">['type'];
jamalsoueidan
jamalsoueidan•3mo ago
The easist way to do that 
import { defineSchema, defineTable } from "convex/server";
import { v, Infer } from "convex/values";

export const DecisionStatus = v.union(
  v.literal("accepted"),
  v.literal("rejected"),
  v.literal("needs_review")
);

export type DecisionStatus = Infer<typeof DecisionStatus >;
import { defineSchema, defineTable } from "convex/server";
import { v, Infer } from "convex/values";

export const DecisionStatus = v.union(
  v.literal("accepted"),
  v.literal("rejected"),
  v.literal("needs_review")
);

export type DecisionStatus = Infer<typeof DecisionStatus >;
` Lets gooooo...
jamalsoueidan
jamalsoueidan•3mo ago
CabalDAO
CabalDAOOP•3mo ago
thank you for this! very helpful

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