MathiasM
Convex Community•2y ago•
5 replies
Mathias

How to call a function within another function?

I would like to get an id from another function, instead of providing the id via args. My use case is that I want to get all users from a group using the current users activeGroupId.

This query gives me the Id that I need:

export const getActiveSpace = internalQuery({
  handler: async (ctx) => {
    const identity = await ctx.auth.getUserIdentity()

    if (!identity) {
      throw new Error("Unauthenticated")
    }

    const userId = identity.subject

    const user = await ctx.db
      .query("users")
      .withIndex("by_user", (q) => q.eq("userId", userId))
      .first()

    if (!user) {
      throw new Error("Not found")
    }

    return user.activeSpace
  },
})


Now, I don't know how to use it in my query to get all members. This is the current code, where the groupId is an empty string, which is the one I want to get replaced by the output of getActiveSpace:

export const getGroupMembers = query({
  handler: async (ctx) => {
    const identity = await ctx.auth.getUserIdentity()

    if (!identity) {
      throw new Error("Unauthenticated")
    }

    const groupId = ""

    const groupMembers = await ctx.db
      .query("groupMembers")
      .withIndex("by_groupId", (q) => q.eq("groupId", groupId))
      .collect()

    const userIds = groupMembers.map((member) => member.userId)

    const users = await Promise.all(
      userIds.map((id) => ctx.db.get(id as Id<"users">))
    )

    return users.filter((user) => user !== null)
  },
})


Can you point me in towards a ressource or help me what I missed to get it to work? There might also be a simpler solution.
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