ballingt•16mo ago

Date parsing behavior

That seems like something for us to fix, thanks for pointing it out @CodingWithJamal. Be aware that built-in date parsing with either new Date(s) or Date.parse(s) is inconsistent between runtimes (ie it works differently in Safari) so it's often not recommended.

5 Replies

ballingtOP•16mo ago

I think you can use

const d = new Date(Date.parse(s));

const d = new Date(Date.parse(s));

to get the same parsing behavior. @CodingWithJamal in your case you dont' want a date object, so using Date.parse(s) which returns the datetime in milliseconds since epoch is more direct too;

// works in Convex
const t1 = Date.parse(s);
// does the same thing as above
const t2 = new Date(Date.parse(s)).getTime()
// Doesn't work in Convex currently
const t3 = (new Date(s)).getTime()

// works in Convex
const t1 = Date.parse(s);
// does the same thing as above
const t2 = new Date(Date.parse(s)).getTime()
// Doesn't work in Convex currently
const t3 = (new Date(s)).getTime()

CodingWithJamal•16mo ago

oh okay i see. Thanks, I didnt understand the error and forgot about the runtime limitations I will try this solution

// Schedule a task to destroy the session when it expires
    const time = new Date(Date.parse(args.expires)).getTime() - Date.now();

// Schedule a task to destroy the session when it expires
    const time = new Date(Date.parse(args.expires)).getTime() - Date.now();

okay this works now tom thanks

CodingWithJamal•16mo ago

So im using sessions in the db to save user auth state, and when its created i wanted to create a schedule to delete the session and make sure the user has to re-login. Is this a good idea over convex cron-jobs?

CodingWithJamal•16mo ago

@Tom

ballingtOP•16mo ago

Yeah I think that's fine! You could also save the time that they logged in and anytime you check for session you check whether that time was in the last 24 hours: that way you can tell the difference between a session expiration and a never-before logged in session

Date parsing behavior

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